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긴급도 22/100 심각도 7.8 · 높음 악용확률 3.9%

CVE-2025-39977

Qualys 위협 인텔 · 심각도 5/5 · QID 591802 · ICS
공개 익스플로잇 권한상승 인증 불필요 원격코드실행 CISA KEV
  • CVSS Temporal 8.8 (현재 위협 반영)
  • 익스플로잇 성숙도: PoC (2/4)
  • 공격 위치: 원격
  • 패치: 가능
  • 익스플로잇 프레임워크: GitHub
  • PCI-DSS 관련
In the Linux kernel, the following vulnerability has been resolved:

futex: Prevent use-after-free during requeue-PI

syzbot managed to trigger the following race:

T1 T2

futex_wait_requeue_pi()
futex_do_wait()
schedule()
futex_requeue()
futex_proxy_trylock_atomic()
futex_requeue_pi_prepare()
requeue_pi_wake_futex()
futex_requeue_pi_complete()
/* preempt */

* timeout/ signal wakes T1 *

futex_requeue_pi_wakeup_sync() // Q_REQUEUE_PI_LOCKED
futex_hash_put()
// back to userland, on stack futex_q is garbage

/* back */
wake_up_state(q->task, TASK_NORMAL);

In this scenario futex_wait_requeue_pi() is able to leave without using
futex_q::lock_ptr for synchronization.

This can be prevented by reading futex_q::task before updating the
futex_q::requeue_state. A reference on the task_struct is not needed
because requeue_pi_wake_futex() is invoked with a spinlock_t held which
implies a RCU read section.

Even if T1 terminates immediately after, the task_struct will remain valid
during T2's wake_up_state(). A READ_ONCE on futex_q::task before
futex_requeue_pi_complete() is enough because it ensures that the variable
is read before the state is updated.

Read futex_q::task before updating the requeue state, use it for the
following wakeup.
타임라인
  1. NVD 공개
  2. 첫 보도 CISA Advisories · 지멘스 SIMATIC S7-1500 CPU 1518(F)-4 PN/DP MFP

벡터: CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:H/A:H

NVD 상세 ↗   GitHub Advisory ↗   참고 링크 ↗

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